Clinton Amy
Tuesday, August 9, 2011
The aerodynamic resistance to motion of a car is almost proportional to the square of its velocity. cont below
Let C!/C2 = b^2...ume both are positive...then a = dv/dt yields [1/C2] dv / [b^2 - v^2] = dt..integrating yields [1/(2bC2)] ln{[b + v]/[b-v]} = t + constant,.. constant = [1/(2bC2)] ln{[b+v(0)]/[b-v(0)]}....thus T = [1/(2bC2)] ln {[b-v(0)]/[b+v(0)]}
No comments:
Post a Comment
Newer Post
Older Post
Home
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment