Tuesday, August 9, 2011

The aerodynamic resistance to motion of a car is almost proportional to the square of its velocity. cont below

Let C!/C2 = b^2...ume both are positive...then a = dv/dt yields [1/C2] dv / [b^2 - v^2] = dt..integrating yields [1/(2bC2)] ln{[b + v]/[b-v]} = t + constant,.. constant = [1/(2bC2)] ln{[b+v(0)]/[b-v(0)]}....thus T = [1/(2bC2)] ln {[b-v(0)]/[b+v(0)]}

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